The range of a projectile fired at an angle θ with the horizontal and with an initial velocity of v₀ feet per second is $r = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta$ where r is measured in feet.A golfer strikes a golf ball at 90 feet per second.Ignoring the effects of air resistance,at what angle must the golfer hit the ball so that it travels 150 feet? (Round your answer to the nearest degree. ) A)14° B)36° C)18° D)27° E)41°

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The Answer of The range of a projectile fired at an angle θ with the horizontal and with an initial velocity of v₀ feet per second is $r = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta$ where r is measured in feet.A golfer strikes a golf ball at 90 feet per second.Ignoring the effects of air resistance,at what angle must the golfer hit the ball so that it travels 150 feet? (Round your answer to the nearest degree. ) A)14° B)36° C)18° D)27° E)41°

The Range of a Projectile Fired at an Angle θ r=132v02sin⁡2θr = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \thetar=321​v02​sin2θ

The Range of a Projectile Fired at an Angle θ $r = \frac { 1 } { 32 } v _ { 0 } ^ { 2 } \sin 2 \theta$