A nucleus of the imaginary atom "Woofnium" (73 protons, 97 neutrons), decays by beta emission with a half-life of 26,000 years. After one half-life, the daughter nucleus will be
A) Wafnium (72 protons, 95 neutrons).
B) Wefnium (71 protons, 97 neutrons).
C) Woofnium (73 protons, 97 neutrons) in a lower energy state.
D) Wifnium (74 protons, 96 neutrons).
E) The daughter nucleus cannot be predicted from the information given.

Question

Quizplus · Accepted Answer

In beta decay, a neutron is converted into a proton and an electron (beta particle) is emitted. Therefore, the number of protons increases by 1 (to 74), and the number of neutrons decreases by 1 (to 96), resulting in "Wifnium" (74 protons, 96 neutrons).

A Nucleus of the Imaginary Atom "Woofnium" (73 Protons, 97