Consider the following partial computer output from a simple linear regression analysis. S = 0.4862 R-Sq = ______ Analysis of Variance Determine the 95% confidence interval for the mean value of y when x = 9.00.Givens: $\Sigma$ x = 129.03 and $\Sigma$ x² = 1178.547 A)(.6572 2.829) B)(1.467 2.019) C)(.6718 .2814) D)(1.471 2.015)

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Y = 1.743Distance value = 1/15 + [(9-(129.03/15))²/(1178.547 - (129.03)²/15))] = .068975t statistic = 2.160y $\pm$ (t)(s)( $\sqrt{ dv}$)1.743 $\pm$(2.160)(.4862)($\sqrt{.068975}$)$\to$ 1.467 to 2.019

Consider the Following Partial Computer Output from a Simple Linear Σ\SigmaΣ

Consider the Following Partial Computer Output from a Simple Linear $\Sigma$