There is an average of 22.455 employees at 22 office furniture dealers in a major metropolitan area with a standard deviation of 18.52.Construct a 99% confidence interval for the true mean number of full-time employees at office furniture dealers.

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Quizplus · Accepted Answer

The 99% confidence interval is calculated using the formula: mean ± (z-score * (standard deviation/√n)). For 99% confidence, the z-score is approximately 2.576. Plugging in the values: 22.455 ± (2.576 * (18.52/√22)) gives the interval [11.277, 33.633].

There Is an Average of 22