What is a 95 percent confidence interval for µ when n = 10, 35.6,and s = 13.0? Assume population normality.
A)[26.44 44.76]
B)[26.30 44.90]
C)[33.02 38.18]
D)[27.54 43.66]

Question

What is a 95 percent confidence interval for µ when n = 10,  35.6,and s = 13.0? Assume population normality.
A)[26.44 44.76] 
B)[26.30 44.90] 
C)[33.02 38.18] 
D)[27.54 43.66]

Quizplus · Accepted Answer

Using a t-distribution with n-1 degrees of freedom and a 95% confidence level, the critical value is 2.262.

Thus, the 95% confidence interval can be found as:
x̄ ± t(α/2, n-1)*s/√n
35.6 ± 2.262*(13/√10)
= (26.30, 44.90)

Therefore, the best choice is option B, which gives the correct interval.

What Is a 95 Percent Confidence Interval for µ When