A mass m is traveling at an initial speed v₀= 25.0 m/s.It is brought to rest in a distance of 62.5 m by a force of 15.0 N.The mass is A)37.5 kg B)3.00 kg C)1.50 kg D)6.00 kg E)3.75 kg

Question

Quizplus · Accepted Answer

The work done by the force to bring the mass to rest is equal to the kinetic energy the mass had initially. The work done by the force is $F \times d = 15.0 \, \text{N} \times 62.5 \, \text{m} = 937.5 \, \text{J}$. The initial kinetic energy is given by $\frac{1}{2}mv^2$, where $m$ is the mass and $v$ is the initial velocity. Setting the kinetic energy equal to the work done gives $\frac{1}{2}m(25.0)^2 = 937.5$. Solving for $m$ gives $m = \frac{937.5 \times 2}{625} = 3.00 \, \text{kg}$.

A Mass M Is Traveling at an Initial Speed V0

A Mass M Is Traveling at an Initial Speed V₀