A mass m is traveling at an initial speed v₀= 25.0 m/s.It is brought to rest in a distance of 62.5 m by a force of 15.0 N.The mass is

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The work done by the force to bring the mass to rest is equal to the kinetic energy the mass had initially. The work done by the force is $F \times d = 15.0 \, \text{N} \times 62.5 \, \text{m} = 937.5 \, \text{J}$. The initial kinetic energy is given by $\frac{1}{2}mv^2$, where $m$ is the mass and $v$ is the initial velocity. Setting the kinetic energy equal to the work done gives $\frac{1}{2}m(25.0)^2 = 937.5$. Solving for $m$ gives $m = \frac{937.5 \times 2}{625} = 3.00 \, \text{kg}$.

A Mass M Is Traveling at an Initial Speed V0

A Mass M Is Traveling at an Initial Speed V₀