A 6000-kg truck is accelerating at 0.5 m/s² up a slope of 5 degrees.If the opposing forces due to road friction and air resistance are 80 N per 1000 kg of truck mass,calculate the driving force needed for the truck to accelerate up the incline. A)8100 N B)8600 N C)8200 N D)7700 N E)1700 N

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Quizplus · Accepted Answer

The driving force needed is calculated by summing the force required to overcome gravity, friction, and to provide the acceleration. The gravitational force component along the slope is $6000 \times 9.8 \times \sin(5^\circ)$. The frictional force is $80 \times 6 = 480 \, \text{N}$. The force for acceleration is $6000 \times 0.5 = 3000 \, \text{N}$. Adding these gives the total driving force needed.

A 6000-Kg Truck Is Accelerating at 0