A 5-kg box is pushed 5 m up a plane that is inclined at 30º with the horizontal.The coefficient of kinetic friction between the box and the plane is 0.20.The change in potential energy of the box is approximately
A)12.5 J
B)34.2 J
C)123 J
D)345 J
E)403 J

Question

Quizplus · Accepted Answer

The change in potential energy (ΔPE) of the box is given by ΔPE = mgh, where m is the mass of the box, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height gained. Since the plane is inclined at 30º, the height (h) can be found using the sine function: h = 5m * sin(30º) = 2.5m. Therefore, ΔPE = 5kg * 9.8m/s^2 * 2.5m = 122.5J, which is approximately 123 J.

A 5-Kg Box Is Pushed 5 M Up a Plane