A particle with speed v₁ = 2.64 $\times$ 10⁶ m/s makes a glancing elastic collision with another particle that is at rest.Both particles have the same mass.After the collision,the struck particle moves off at 45º to v₁.The speed of the struck particle after the collision is approximately A)3.4 $\times$ 10⁶ m/s B)1.3 $\times$ 10⁶ m/s C)0.53 $\times$ 10⁶ m/s D)1.9 $\times$ 10⁶ m/s E)6.4 $\times$ 10⁶ m/s

Question

Quizplus · Accepted Answer

In an elastic collision where both particles have the same mass and one is initially at rest, the velocities of the particles after the collision are perpendicular to each other if one particle moves off at 45º. Using conservation of momentum and energy, the speed of the struck particle can be found using the initial speed and the angle. The speed of the struck particle is $v = v_0 \cos(45^\circ) = 2.64 \times \frac{\sqrt{2}}{2} \approx 1.9 \times 10^{6} \, \text{m/s}$.

A Particle with Speed V1 = 2 ×\times× 106 M/s Makes a Glancing Elastic Collision with Another Particle

A Particle with Speed V₁ = 2 $\times$ 10⁶ M/s Makes a Glancing Elastic Collision with Another Particle