A 5 $\times$ 10^-6-kg dot of paint on the side of a rotating cylinder flies off when the angular speed of the cylinder reaches 5 $\times$ 10³ rad/s.The spin axis of the cylinder is vertical and its radius is 0.04 m.The force of adhesion between the paint and the surface is approximately A)1 N B)1 mN C)5 mN D)5 kN E)5 N

Question

Quizplus · Accepted Answer

The force of adhesion can be found using the centripetal force formula, $F = m \cdot r \cdot \omega^2$, where $m$ is the mass of the paint dot (0.01 kg), $r$ is the radius of the cylinder (0.04 m), and $\omega$ is the angular speed (300 rad/s). Plugging in the values, $F = 0.01 \cdot 0.04 \cdot 300^2 = 3.6 N$, which is approximately 5 N, indicating that the force of adhesion is about 5 N.

A 5 ×\times× 10-6-Kg Dot of Paint on the Side of a Rotating

A 5 $\times$ 10^-6-Kg Dot of Paint on the Side of a Rotating