A 0.3-kg object is being whirled in a horizontal circle at the end of a 1.5 m long string.If the string breaks when the number of revolutions per minute,rpm = 200,then find the maximum tension in the string. A)2.0 $\times$ 10² N B)59 N C)7.0 $\times$ 10⁵ N D)9.0 N E)88 N

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Quizplus · Accepted Answer

The maximum tension in the string is given by:T = mv^2/rwhere m is the mass of the object, v is its speed, and r is the radius of the circle.We can find the speed of the object using the formula:v = 2πrf/60where f is the frequency in revolutions per minute.Substituting the given values, we get:v = 2π(1.5 m)(200 rpm/60) = 15.71 m/sNow we can calculate the tension:T = (0.3 kg)(15.71 m/s)^2/1.5 m = 70.0 NTherefore, the maximum tension in the string is 70.0 N, which is closest to choice A.

A 03-Kg Object Is Being Whirled in a Horizontal Circle at at the End