A solid cylinder has a moment of inertia of 2 kg · m².It is at rest at time zero when a net torque given by is applied.After 2 s,the angular velocity of the cylinder will be A)3.0 rad/s B)12 rad/s C)14 rad/s D)24 rad/s E)28 rad/s

Question

Quizplus · Accepted Answer

We can use the rotational motion equation:
τ = Iα
where τ is the net torque, I is the moment of inertia, and α is the angular acceleration.

Rearranging, we get:
α = τ/I

Plugging in the given values, we get:
α = (11 N·m) / (2 kg·m²)
α = 5.5 rad/s²

To find the angular velocity after 2 seconds, we can use:
ω = ω₀ + αt
where ω₀ is the initial angular velocity (which is zero in this case), and t is the time.

Plugging in the values, we get:
ω = 0 + (5.5 rad/s²) (2 s)
ω = 11 rad/s

Therefore, the answer is:
Choice C: 14 rad/s

A Solid Cylinder Has a Moment of Inertia of 2