In the figure,the rotational inertia of the wheel and axle about the center is 12.0 kg · m²,the constant force F is 39.2 N,and the radius r is 0.800 m.The wheel starts from rest.When the force has acted through 2.00 m,the rotational velocity $\omega$acquired by the wheel due to this force will be A)1.26 rad/s B)3.33 rad/s C)3.61 rad/s D)6.24 rad/s E)10.3 rad/s

Question

Quizplus · Accepted Answer

We can use the formula for rotational motion with constant force: $\omega = \sqrt{\frac{2F\cdot r}{I}}$, where $\omega$ is the final angular velocity, $F$ is the force applied, $r$ is the radius, and $I$ is the rotational inertia. Plugging in the given values, we get $\omega = \sqrt{\frac{2(39.2\;N)(0.800\;m)}{12.0\;kg\cdot m^2}} \approx 3.61\;rad/s$. Therefore, the answer is (C).

In the Figure,the Rotational Inertia of the Wheel and Axle ω\omegaω

In the Figure,the Rotational Inertia of the Wheel and Axle $\omega$