A constant torque of 15 N · m acts for 3.0 s on a system of mass 2.0 kg.The change in angular momentum of the system during this period of time is A)5.0 kg · m²/s B)7.5 kg · m²/s C)10 kg · m²/s D)23 kg · m²/s E)45 kg · m²/s

Question

Quizplus · Accepted Answer

The change in angular momentum can be calculated using the formula $\Delta L = \tau \Delta t$, where $\Delta L$ is the change in angular momentum, $\tau$ is the torque, and $\Delta t$ is the time interval. Substituting the given values, $\Delta L = 15 \, \text{N} \cdot \text{m} \times 3.0 \, \text{s} = 45 \, \text{kg} \cdot \text{m}^2/\text{s}$.

A Constant Torque of 15 N · M Acts for 3.0