A wire 2.5-m long has a cross-sectional area of 2.5 mm².It is hung vertically,and a 4.5-kg mass is hung from it.By how much does the wire stretch if Young's modulus for that material is 2.0 $\times$ 10¹¹ N/m²? A)0.22 mm B)2.2 mm C)0.022 mm D)0.72 mm E)0.072 mm

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Quizplus · Accepted Answer

The stretch ($\Delta L$) can be calculated using the formula $\Delta L = \frac{FL}{AY}$, where $F$ is the force applied (in this case, weight = mass $\times$ gravity = 4.5 kg $\times$ 9.8 m/s$^2$), $L$ is the original length of the wire (2.5 m), $A$ is the cross-sectional area (2.5 mm$^2$ = 2.5 $\times$ 10$^{-6}$ m$^2$), and $Y$ is Young's modulus (2.0 $\times$ 10$^{11}$ N/m$^2$). Substituting these values gives a stretch of approximately 0.22 mm.

A Wire 25-M Long Has a Cross-Sectional Area of 2 ×\times×

A Wire 25-M Long Has a Cross-Sectional Area of 2 $\times$