A tube with a radius of 4.2 cm is holding oil that has a density of 0.92 g/cm³.The pressure in the oil at a depth of 64 cm from the top of the surface is A)5.8 $\times$ 10² Pa B)5.8 $\times$ 10³ Pa C)1.0 $\times$ 10² Pa D)1.0 $\times$ 10⁶ Pa E)1.7 $\times$ 10³ Pa

Question

Quizplus · Accepted Answer

We can use the formula P = ρgh, where P is pressure, ρ is density of the fluid, g is acceleration due to gravity, and h is the depth of the fluid. 
Substituting the given values, we get 
P = (0.92 g/cm³)(9.8 m/s²)(0.64 m) = 5.84 x 10³ Pa = 5.8 x 10⁴ Pa (to 2 significant figures) 
Note that we converted cm to m for consistency in units. 
Therefore, the closest answer choice is B, which is 5.8 x 10⁴ Pa.

A Tube with a Radius of 4 ×\times× 102 Pa B)5 ×\times×

A Tube with a Radius of 4 $\times$ 10² Pa
B)5 $\times$