The force constant of a massless spring is 25.0 N/m.A mass of 0.45 kg is oscillating in simple harmonic motion at the end of the spring with an amplitude of 0.32 m.The maximum speed of the mass is
A)5.7 m/s
B)56 m/s
C)7.4 m/s
D)2.4 m/s
E)10 m/s

Question

Quizplus · Accepted Answer

The maximum speed (v_max) in simple harmonic motion is given by v_max = ωA, where ω = sqrt(k/m). Here, k = 25.0 N/m, m = 0.45 kg, and A = 0.32 m. Calculating ω gives ω = sqrt(25.0/0.45) = 7.45 rad/s. Therefore, v_max = 7.45 * 0.32 = 2.38 m/s, which is approximately 2.4 m/s.

The Force Constant of a Massless Spring Is 25