A particle is oscillating with simple harmonic motion.The frequency of the motion is 10 Hz and the amplitude of the motion is 5.0 cm.As the particle passes its central equilibrium position,the acceleration of the particle is A)100 cm/s² B)1.6 $\times$ 10⁵ cm/s² C)4 $\times$ 10⁶ cm/s² D)zero E)3.2 $\times$ 10⁶ cm/s²

Question

Quizplus · Accepted Answer

The acceleration of a particle in simple harmonic motion is given by a = -ω²x, where ω is the angular frequency (2πf in this case) and x is the displacement from equilibrium. At the equilibrium position, x = 0 and therefore a = 0 as well. So, the correct answer is D) zero.

A Particle Is Oscillating with Simple Harmonic Motion ×\times× 105 Cm/s2 C)4

A Particle Is Oscillating with Simple Harmonic Motion $\times$ 10⁵ Cm/s²
C)4