A giant simple pendulum has a time period of 5.0 s.If the time period is changed to 4.5 s,calculate the change in the length of the string if g is constant at 9.81 m/s². A)1.2 m shorter B)0.8 m longer C)1.2 m longer D)0.8 m shorter E)None of the above

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Quizplus · Accepted Answer

The time period of a simple pendulum is given by:T = 2π√(L/g)where L is the length of the string and g is the acceleration due to gravity.If the time period is changed from 5.0 s to 4.5 s, then:4.5 = 2π√(L/9.81)5.0 = 2π√(L'/9.81)Dividing the first equation by the second equation, we get:4.5/5.0 = √(L/L')0.9 = √(L/L')L/L' = 0.81L' = L/0.81L' = 1.23LTherefore, the length of the string must be increased by 1.23L - L = 0.23L.

A Giant Simple Pendulum Has a Time Period of 5