Two monoatomic gases,helium and neon,are mixed in the ratio of 2 to 1 and are in thermal equilibrium at temperature T (the molar mass of helium = 4.0 g/mol and the molar mass of neon = 20.2 g/mol).If the average kinetic energy of each helium atom is 6.3 $\times$ 10^-21 J,calculate the temperature T. A)304 K B)456 K C)31 K D)31 $\circ$ C E)101 K

Question

Quizplus · Accepted Answer

The average kinetic energy of a monoatomic gas is given by the formula:

KE = (3/2)kT

Where k is the Boltzmann constant and T is the temperature in Kelvin.

We are given the average kinetic energy of each helium atom, which is:

KE(He) = 6.3 x 10^-21 J

We can use this to find the temperature T:

6.3 x 10^-21 J = (3/2)kT

T = (2/3)(6.3 x 10^-21 J)/(1.38 x 10^-23 J/K) ≈ 304 K

Since the ratio of helium to neon is 2:1, the temperature of the mixture is the same as the temperature of the helium gas, which is 304 K. Therefore, the correct answer is A.

Two Monoatomic Gases,helium and Neon,are Mixed in the Ratio of 2