The pressure of a mass of air at 20 $\circ$ C is halved adiabatically.If the ratio of C_p to C_v for air is 1.41,calculate the resulting temperature.

Question

Quizplus · Accepted Answer

Using the adiabatic process formula $ T_2 = T_1 \left( \frac{P_2}{P_1} \right)^{(\gamma-1)/\gamma} $, where $ \gamma = 1.41 $, $ T_1 = 20°C $, and $ P_2/P_1 = 0.5 $, the resulting temperature $ T_2 $ is approximately -33.0°C.

The Pressure of a Mass of Air at 20 ∘\circ∘ C Is Halved Adiabatically

The Pressure of a Mass of Air at 20^$\circ$C Is Halved Adiabatically