The Carnot efficiency for a heat engine operating between the temperatures of 227º C and 27ºC is

Question

Quizplus · Accepted Answer

The Carnot efficiency equation is given by:
Efficiency = (T_hot - T_cold) / T_hot
Where T_hot is the temperature of the hot reservoir and T_cold is the temperature of the cold reservoir.

In this case, T_hot = 227ºC + 273 = 500K and T_cold = 27ºC + 273 = 300K.

Therefore, the efficiency = (500 - 300) / 500 = 40%.

Hence, the correct option is C) 40%.

The Carnot Efficiency for a Heat Engine Operating Between the Temperatures