Two moles of a gas at T = 350 K expand quasistatically and isothermally from an initial volume of 20 L to a final volume of 60 L.The change in entropy of the gas during this expansion is (R = 8.314 J/mol·K)

Question

Quizplus · Accepted Answer

The change in entropy ($\Delta S$) for an isothermal process can be calculated using the formula $\Delta S = nR\ln\frac{V_f}{V_i}$, where $n$ is the number of moles, $R$ is the gas constant, $V_f$ is the final volume, and $V_i$ is the initial volume. Plugging in the given values: $\Delta S = 2 \times 8.314 \times \ln\frac{60}{20} = 2 \times 8.314 \times \ln3 \approx 18.3$ J/K.

Two Moles of a Gas at T = 350 K