The coefficient of thermal expansion of water at 20ºC is 0.207 $\times$ 10 ^-3 K ^-1.A thin glass tube contains a 75.0 cm column of water at 20ºC.If the thermal expansion of the glass tube is negligible,by how much does the length of the column of water expand when it is heated to 80ºC? A)3.1 mm B)9.3 mm C)12.4 mm D)4.1 mm E)28 mm

Question

Quizplus · Accepted Answer

The formula to calculate the thermal expansion of water is:

ΔL = L₀αΔT

where ΔL is the change in length, L₀ is the initial length, α is the coefficient of thermal expansion (given in the problem), and ΔT is the change in temperature (final temperature - initial temperature).

Using this formula, we can calculate:

ΔL = (75.0 cm)(0.207 × 10^-4 K^-1)(80ºC - 20ºC)
ΔL = 9.3 mm

Therefore, the column of water will expand by 9.3 mm when heated from 20ºC to 80ºC.

The answer is B.

The Coefficient of Thermal Expansion of Water at 20ºC Is ×\times×

The Coefficient of Thermal Expansion of Water at 20ºC Is $\times$