A uniform line charge of linear charge density $\lambda$ = 10.0 nC/m extends from x = 5 m to x = 8 m.The magnitude of the electric field at x = 10 m is

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The electric field of a line charge is given by:$$E = \frac{1}{4\pi\varepsilon_0} \frac{2\lambda}{r}$$where:* E is the electric field* \varepsilon_0 is the permittivity of free space* \lambda is the linear charge density* r is the distance from the line chargeIn this problem, we have:* \lambda = 10.0 nC/m* r = 10 mPlugging these values into the equation, we get:$$E = \frac{1}{4\pi(8.85	imes10^{-12} 	ext{ C}^2/	ext{Nm}^2)} \frac{2(10.0	imes10^{-9} 	ext{ C/m})}{10 	ext{ m}}$$$$E = 27.0 	ext{ N/C}$$Therefore, the correct answer is A.

A Uniform Line Charge of Linear Charge Density λ\lambdaλ = 100 NC/m Extends from X = 5 M to X

A Uniform Line Charge of Linear Charge Density $\lambda$ = 100 NC/m Extends from X = 5 M to X