A spherical shell of radius 9.0 cm carries a uniform surface charge density $\sigma$ = 9.0 nC/m².The electric field at r = 16 cm is approximately A)0.32 kN/C B)1.0 kN/C C)zero D)0.13 kN/C E)0.53 kN/C

Question

Quizplus · Accepted Answer

The electric field due to a uniformly charged spherical shell at a point outside the shell can be found by using the expression:

E = k σ R / r^2

where k is the Coulomb constant, σ is the surface charge density, R is the radius of the spherical shell, and r is the distance from the center of the shell to the point where the electric field is being measured.

Substituting the given values, we get:

E = (9 × 10^9 Nm^2/C^2) × (9 × 10^(-9) C/m^2) × 0.09 m / (0.16 m)^2

E ≈ 0.53 kN/C

Therefore, the best choice is (E) with an explanation as shown above.

A Spherical Shell of Radius 9 σ\sigmaσ = 90 NC/m2

A Spherical Shell of Radius 9 $\sigma$ = 90 NC/m²