An electric dipole that has a positive charge of 4.80 × 10^-¹⁹ C is separated from a negative charge of the same magnitude by 6.40 × 10^-¹⁰ m.The magnitude of the electric field at the midpoint of the dipole is

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The electric field at the midpoint of a dipole is given by:$$E = \frac{1}{4\pi\varepsilon_0} \frac{2q}{r^3}$$where:* q is the magnitude of the charge on each dipole* r is the distance between the charges* $\varepsilon_0$ is the permittivity of free spacePlugging in the given values, we get:$$E = \frac{1}{4\pi(8.85	imes10^{-12}	ext{ C}^2/	ext{Nm}^2)} \frac{2(4.80	imes10^{-19}	ext{ C})}{(6.40	imes10^{-10}	ext{ m})^3}$$$$E = 8.44	imes10^{10}	ext{ N/C}$$

An Electric Dipole That Has a Positive Charge of 4