Two charges Q₁ (= +6  C)and Q₂ (= -2  C)are brought from infinity to positions on the x-axis of x = -4 cm and x = +4 cm,respectively.Is it possible to bring a third charge Q₃ (= +3  C)from infinity to a point on the x-axis between the charges where the potential is zero,and if so,where would this position be? A)it is not possible B)x = 0 cm C)x = +2 cm D)x = +6 cm E)x = +1.5 cm

Question

Quizplus · Accepted Answer

First, we need to calculate the potential at each charge's position:
V1 = k*q1/x1 = 9*10^9 * 6 / 0.04 = 1.35*10^12 V
V2 = k*q2/x2 = 9*10^9 * (-2) / 0.04 = -4.5*10^11 V

To find the position where the potential is zero, we can use the principle of superposition and set the total potential to zero:

V1 + V2 + k*q3/x3 = 0

Substituting the values we get:

1.35*10^12 - 4.5*10^11 + 9*10^9 * 3 / x3 = 0

Solving for x3:

x3 = 2 cm

Therefore, the answer is C: x = +2 cm.

Two Charges Q1 (= +6 C)and Q2 (= -2

Two Charges Q₁ (= +6 C)and Q₂ (= -2