The potential of a spherical shell carrying 6.0  C of charge is 540 kV.What is the radius of the shell? A)1.0  10¹ m B)1.0  10² m C)3.2  10^-1 m D)1.0  10^-1 m E)none of the above

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Quizplus · Accepted Answer

The potential V of a spherical shell is given by V = kQ/R, where k is Coulomb's constant (9 x 10^9 Nm²/C²), Q is the charge (6.0 x 10^-6 C), and R is the radius. Solving for R gives R = kQ/V = (9 x 10^9 x 6.0 x 10^-6) / 540,000 = 1.0 x 10^-1 m.

The Potential of a Spherical Shell Carrying 6