The electrostatic potential energy of two protons separated by 2.6  10^-15 m is approximately A)zero B)4.7  10^-34 J C)4.3  10^-24 J D)3.8  10^-14 J E)8.9  10^-14 J

Question

Quizplus · Accepted Answer

The electrostatic potential energy between two protons can be calculated using the formula $ U = \frac{k \cdot e^2}{r} $, where $ k $ is Coulomb's constant ($ 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 $), $ e $ is the charge of a proton ($ 1.6 \times 10^{-19} \, \text{C} $), and $ r $ is the separation distance. Substituting the given values, the potential energy is approximately $ 8.9 \times 10^{-14} \, \text{J} $.

The Electrostatic Potential Energy of Two Protons Separated by 2