If a capacitor of capacitance 2.0 µF is given a charge of 1.0 mC,the potential difference across the capacitor is
A)0.50 kV
B)2.0 V
C)2.0 µV
D)0.50 V
E)None of these is correct.

Question

Quizplus · Accepted Answer

The potential difference (V) across a capacitor can be calculated using the formula V = Q/C, where Q is the charge (in coulombs) and C is the capacitance (in farads). Given Q = 1.0 mC = 1.0 × 10^-3 C and C = 2.0 µF = 2.0 × 10^-6 F, V = (1.0 × 10^-3) / (2.0 × 10^-6) = 0.5 × 10^3 V = 0.50 kV.

If a Capacitor of Capacitance 2