A 2.0-µF capacitor has a potential difference of 5000 V.The work done in charging it was
A)2.5 J
B)5.0 J
C)25 J
D)5.0 mJ
E)0.50 kJ

Question

Quizplus · Accepted Answer

The work done in charging a capacitor is given by the formula: W = 1/2 CV^2
where C is the capacitance and V is the potential difference across the capacitor.
Substituting the given values, we get:
W = 1/2 x 2.0 x 10^-6 x (5000)^2
W = 25 J
Therefore, the correct choice is C.

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