Use the following figure to answer the next problem: -You connect three capacitors as shown in the diagram.C₁ = 5.0 $\mu$F,C₂ = 4.0 $\mu$F,and C₃ = 3.0 $\mu$F.If you apply 12 V between points A and B,the energy stored in C₃ will be approximately A)0.16 mJ B)41 $\mu$J C)0.12 mJ D)0.41 mJ E)16 mF

Question

Quizplus · Accepted Answer

The capacitance between points A and B (in parallel with CS1U1B0) is Ceq = C1 + C2 + C3 = 5 + 4 + 3 = 12 F.

The charge Q stored in the capacitors will be the same, so we can use the formula Q = CV, where V = 12 V is the voltage difference between points A and B.

Thus, Q = (12 F)(12 V) = 144 C.

The energy stored in a capacitor is given by the formula U = (1/2)CV^2.

For CS1U1B13S1U1B0, the energy stored is U = (1/2)(3 F)(12 V)^2 = 216 J = 0.12 mJ (since 1 J = 10^-3 mJ).

Therefore, the answer is (C) 0.12 mJ.

Use the Following Figure to Answer the Next Problem μ\muμ

Use the Following Figure to Answer the Next Problem $\mu$