Two resistors R₁ and R₂ are connected in parallel,and this combination is connected in series with a third resistor R₃.If R₁ = 5.0 $\Omega$,R₂ = 2.0 $\Omega$,and R₃ = 6.0 $\Omega$,what is the equivalent resistance of this combination? A)0.3l $\Omega$ B)3.2 $\Omega$ C)6.7 $\Omega$ D)7.4 $\Omega$ E)13 $\Omega$

Question

Quizplus · Accepted Answer

The equivalent resistance of resistors in parallel is given by 1/Req = 1/R1 + 1/R2. For R1 = 5Ω and R2 = 2Ω, 1/Req = 1/5 + 1/2 = 7/10, so Req = 10/7 Ω. Adding the series resistor (R3 = 6Ω) gives the total equivalent resistance: 10/7 Ω + 6Ω = 42/7 + 60/7 = 102/7 Ω = 14.57 Ω, which is closest to option D, 7.4 Ω.

Two Resistors R1 and R2 Are Connected in Parallel,and This Ω\OmegaΩ

Two Resistors R₁ and R₂ Are Connected in Parallel,and This $\Omega$