A beam of charged particles moving with a speed of 10⁶ m/s enters a uniform magnetic field of 0.1 T at right angles to the direction of motion.If the particles move in a radius of 0.2 m,then calculate their period of motion. A)6.3 $\times$ 10^-7 s B)1.3 $\times$ 10^-7 s C)1.3 $\times$ 10^-6 s D)4.1 $\times$ 10^-7 s E)none of the above

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Quizplus · Accepted Answer

The period of motion T for a charged particle in a magnetic field is given by T = 2πm/qB. Using the relation v = rω = rqB/m, we find T = 2πr/v. Substituting r = 0.2 m and v = 10^6 m/s, we get T = 2π(0.2)/(10^6) = 1.3 × 10^-6 s.

A Beam of Charged Particles Moving with a Speed of 106

A Beam of Charged Particles Moving with a Speed of 10⁶