A cylindrical bar magnet of radius 1.00 cm and length 10.0 cm has a magnetic dipole moment of magnitude m = 2.00 A · m².What is the magnetization M,assuming it to be uniform in the magnet? A)2.53 $\times$ 10⁴ A/m B)6.37 $\times$ 10⁴ A/m C)3.18 $\times$ 10⁴ A/m D)1.86 $\times$ 10⁴ A/m E)3.18 $\times$ 10² A/m

Question

Quizplus · Accepted Answer

The magnetization $M$ is given by $M = \frac{m}{V}$, where $m$ is the magnetic dipole moment and $V$ is the volume of the cylinder. The volume $V$ of the cylinder is $\pi r^2 h = \pi (0.01\,m)^2 (0.1\,m) = 3.14 \times 10^{-4}\,m^3$. Given $m = 2.00\,A\cdot m^2$, $M = \frac{2.00}{3.14 \times 10^{-4}} = 6.37 \times 10^3\,A/m$.

A Cylindrical Bar Magnet of Radius 1 ×\times× 104 A/m B)6 ×\times×

A Cylindrical Bar Magnet of Radius 1 $\times$ 10⁴ A/m
B)6 $\times$