If m = m_B (in a paramagnetic material)for an external magnetic field of 6 T,what fraction of the saturation magnetization is M at 300 K? A)8.06 $\times$ 10^-2 B)1.34 $\times$ 10^-2 C)7.46 $\times$ 10^-3 D)4.48 $\times$ 10^-3 E)4.03 $\times$ 10^-2

Question

Quizplus · Accepted Answer

Using the equation M=mB/exp(kT) with k=1.38x10^-23 J/K, T=300 K and B=6 T, we can calculate M.

M=mB/exp(kT) = mS1U1B1BS1U1B0/exp(kT)

=8.06x10^10 S1U1P-2 S1S1P0

Fraction of saturation magnetization is M/mS1U1B1BS1U1B0 = 4.48x10^-3 S1U1P-3 S1S1P0, which is equivalent to 4.48% of the saturation magnetization. Therefore, the answer is D.

If M = MB (In a Paramagnetic Material)for an External ×\times×

If M = M_B (In a Paramagnetic Material)for an External $\times$