A solenoid 50 cm long with a radius of 5.0 cm has 800 turns.You find that it carries a current of 10 A.The magnetic flux through it is approximately

Question

Quizplus · Accepted Answer

The magnetic flux through a solenoid is given by the equation:
Φ = μ₀nIA
where Φ is the magnetic flux, μ₀ is the permeability of free space (4π×10⁻⁷ T·m/A), n is the number of turns per unit length (n = N/l), I is the current, and A is the cross-sectional area.
The cross-sectional area of the solenoid is A = πr² = π(0.05 m)² = 0.00785 m².
The number of turns per unit length is n = N/l = 800/0.5 = 1600 turns/m.
Therefore, the magnetic flux through the solenoid is:
Φ = μ₀nIA = (4π×10⁻⁷ T·m/A)(1600 turns/m)(10 A)(0.00785 m²) = 0.9856 mWb
which is approximately 98 mWb. Thus, the best choice is C.

A Solenoid 50 Cm Long with a Radius of 5