A straight conductor 10 cm long is perpendicular to a uniform magnetic field of flux density 2.0 mT.When the conductor carries a current of 5.0 A,the force exerted on it by the field is
A)0.25 kN
B)40 $\mu$N
C)1.0 mN
D)zero
E)5.0 mN

Question

Quizplus · Accepted Answer

The force exerted on a straight conductor of length L carrying a current I and lying perpendicular to a magnetic field of flux density B is given by the equation:
F = BILsinθ
where θ is the angle between the direction of the current and the direction of the magnetic field. In this case, θ = 90°, so sinθ = 1.
Substituting the given values, we get:
F = (2.0 × 10^-3 T) × (5.0 A) × (10 cm) × (1/100 cm/m) × (1) = 1.0 × 10^-3 N = 1.0 mN.
Therefore, the correct choice is C.

A Straight Conductor 10 Cm Long Is Perpendicular to a Uniform