You place a 50-mH inductor across an AC generator that has a maximum EMF of 120 V.The inductive reactance when the frequency is 60 Hz is approximately
A)3.0 $\Omega$
B)0.31 $\Omega$
C)6.0 $\Omega$
D)47 $\Omega$
E)19 $\Omega$

Question

Quizplus · Accepted Answer

The inductive reactance (X_L) is calculated using the formula X_L = 2πfL, where f is the frequency and L is the inductance. Substituting the given values, X_L = 2π(60 Hz)(0.050 H) ≈ 18.85 Ω, which is approximately 19 Ω.

You Place a 50-MH Inductor Across an AC Generator That Ω\OmegaΩ

You Place a 50-MH Inductor Across an AC Generator That $\Omega$