A 10-mH inductor has an internal resistance of 10 $\Omega$.The impedance of this inductor for a frequency of 60 Hz is approximately
A)3.77 $\Omega$
B)10 $\Omega$
C)13.8 $\Omega$
D)10.6 $\Omega$
E)none of these is correct

Question

Quizplus · Accepted Answer

The impedance of the inductor can be calculated as:
Z = √(R^2 + Xl^2) where R is the internal resistance and Xl is the inductive reactance.
Xl = 2πfL where f is the frequency and L is the inductance.
Substituting the given values, we get:
Xl = 2π(60)(10×10^-3) = 3.77 Ω 
Z = √(10^2 + 3.77^2) = 10.6 Ω, approximately.
Therefore, the closest option is C, which is 13.8 Ω.

A 10-MH Inductor Has an Internal Resistance of 10 Ω\OmegaΩ The Impedance of This Inductor for a Frequency of 60

A 10-MH Inductor Has an Internal Resistance of 10 $\Omega$ The Impedance of This Inductor for a Frequency of 60