A series RLC circuit is driven by a 1.0-kHz oscillator.The circuit parameters are L = 5.0 mH,C = 4.0 $\mu$F,R = 10 $\Omega$.What is the resonance frequency of the circuit?
A)1.1 kHz
B)7.1 kHz
C)11 kHz
D)36 Hz
E)36 kHz

Question

Quizplus · Accepted Answer

The resonance frequency $f_0$ of an RLC circuit is given by $f_0 = \frac{1}{2\pi\sqrt{LC}}$, where $L$ is the inductance in henries (H) and $C$ is the capacitance in farads (F). Plugging in the given values, $L = 5.0 \times 10^{-3}$ H and $C = 4.0 \times 10^{-6}$ F, we get $f_0 = \frac{1}{2\pi\sqrt{(5.0 \times 10^{-3})(4.0 \times 10^{-6})}} \approx 1.1 \times 10^3$ Hz or 1.1 kHz.

A Series RLC Circuit Is Driven by a 1 μ\muμ F,R = 10

A Series RLC Circuit Is Driven by a 1 $\mu$ F,R = 10