The maximum kinetic energy of electrons ejected from barium (whose work function is 2.50 eV)when it is illuminated by light of wavelength 350 nm is
A)0.20 eV
B)0.41 eV
C)0.63 eV
D)0.95 eV
E)1.05 eV

Question

Quizplus · Accepted Answer

The energy of the incident light is calculated using E = hc/λ, where h is Planck's constant and c is the speed of light. For 350 nm light, E ≈ 3.54 eV. The maximum kinetic energy is the incident energy minus the work function: 3.54 eV - 2.50 eV = 1.04 eV, which is closest to 1.05 eV.

The Maximum Kinetic Energy of Electrons Ejected from Barium (Whose