The work function for a metal is 5.58 eV.What is the threshold wavelength for the photoelectric effect of incident photons? A)2.22 $\times$ 10^-7 m B)2.22 $\times$ 10^-9 m C)4.50 $\times$ 10⁶ m D)4.50 $\times$ 10^-6 m E)2.22 $\times$ 10^-11 m

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Quizplus · Accepted Answer

The threshold wavelength can be calculated using the equation $\lambda = \frac{hc}{\phi}$, where $h$ is Planck's constant (6.626 x 10$^{-34}$ J·s), $c$ is the speed of light (3.00 x 10$^8$ m/s), and $\phi$ is the work function in joules. First, convert the work function from eV to joules (1 eV = 1.602 x 10$^{-19}$ J), which gives $\phi = 5.58 \times 1.602 \times 10^{-19}$ J. Then, calculate $\lambda$, which results in a value in meters that corresponds to choice A when the correct conversion and calculations are applied.

The Work Function for a Metal Is 5 ×\times× 10-7 M B)2

The Work Function for a Metal Is 5 $\times$ 10^-7 M
B)2