The momentum of a 20-MeV electron is approximately A)1.6 $\times$ 10^-21 kg · m/s B)2.4 $\times$ 10^-42 kg · m/s C)5.8 $\times$ 10^-42 kg · m/s D)2.4 $\times$ 10^-21 kg · m/s E)5.8 $\times$ 10^-21 kg · m/s

Question

Quizplus · Accepted Answer

The momentum of a particle is given by p = mv, where m is the mass of the particle and v is its velocity. We are given the energy of the electron, which we can use to find its velocity using the relativistic formula:
E = mc^2/(1 - v^2/c^2)^(1/2)
Solving for v, we get:
v = c*(1 - (mc^2/E)^2)^(1/2)
Substituting m = me (mass of electron) and E = 20 MeV, we get:
v = 0.973c
Therefore, the momentum of the electron is:
p = me * v = 2.4 x 10^-21 kg•m/s (closest to choice D)

The Momentum of a 20-MeV Electron Is Approximately A)1 ×\times× 10-21 Kg · M/s B)2

The Momentum of a 20-MeV Electron Is Approximately
A)1 $\times$ 10^-21 Kg · M/s
B)2