An electron confined to a one-dimensional box of length L = 0.3 nm makes a transition from state n = 4 to state n = 2.The wavelength of the photon emitted is

Question

Quizplus · Accepted Answer

The energy of the emitted photon is given by:
ΔE = En=2 − En=4= (n=2)²h²/(8mL²) − (n=4)²h²/(8mL²)
where h is the Planck constant and m is the mass of the electron.
Substituting the given values, we get ΔE = 2.036 eV.
The energy of a photon is given by E = hc/λ, where c is the speed of light and λ is the wavelength of the photon.
Substituting the given values, we get λ = hc/ΔE = 28.9 nm (option C).

An Electron Confined to a One-Dimensional Box of Length L