In the Bohr Model of the hydrogen atom,what is the potential energy of the electron in the n = 11 orbit? (The radius of the 1st Bohr orbit is 0.0529 nm.) A)2.25 $\times$ 10^-1 eV B)1.12 $\times$ 10^-1 eV C)5.62 $\times$ 10^-2 eV D)2.47 eV E)None of these is correct.

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The potential energy of the electron in the n = 11 orbit is given by:$$U = -\frac{1}{4\pi\varepsilon_0}\frac{e^2}{r}$$where:* $$\varepsilon_0$$ is the permittivity of free space* e is the charge of the electron* r is the radius of the orbitSubstituting the given values into the equation, we get:$$U = -\frac{(9	imes10^9	ext{ N}\cdot	ext{m}^2/	ext{C}^2)(1.6	imes10^{-19}	ext{ C})^2}{11(0.0529	imes10^{-9}	ext{ m})}$$$$U = -2.25	imes10^{-19}	ext{ J}$$Converting to electron volts, we get:$$U = -2.25	imes10^{-19}	ext{ J}\left(\frac{1	ext{ eV}}{1.6	imes10^{-19}	ext{ J}}ight)$$$$U = -1.12	imes10^{-1}	ext{ eV}$$Therefore, the correct answer is A.

In the Bohr Model of the Hydrogen Atom,what Is the Potential