The energy of a quantum of radiation in a vacuum that has a wavelength of 447 nm is approximately A)2.37 $\times$ 10^-19 J B)1.60 $\times$ 10^-19 J C)9.88 $\times$ 10^-33 J D)9.11 $\times$ 10^-31 J E)None of these is correct.

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The Answer of The energy of a quantum of radiation in a vacuum that has a wavelength of 447 nm is approximately A)2.37 $\times$ 10^-19 J B)1.60 $\times$ 10^-19 J C)9.88 $\times$ 10^-33 J D)9.11 $\times$ 10^-31 J E)None of these is correct.

The Energy of a Quantum of Radiation in a Vacuum ×\times×

The Energy of a Quantum of Radiation in a Vacuum $\times$