A K_$\beta$ X-ray line of wavelength 0.1641 nm is emitted by a certain metal.What is the value of Z and which element is it?

Question

Quizplus · Accepted Answer

The KF1F1F1S1_F1F1F10 X-ray line corresponds to the K-alpha transition, which originates from the n=2 to n=1 energy level transition in the atom. The wavelength of this X-ray line is related to the atomic number (Z) of the element according to the Moseley's law: λ = (Z - b)^2 / (n - δ)^2 where λ is the wavelength of the X-ray line, b is a constant, n is the principal quantum number, and δ is a screen constant. For the K-alpha transition, n = 2 and δ = 1, so we can simplify the equation to: Z = (λ(n - δ)/2)^0.5 + b Using the given wavelength of 0.1641 nm, and assuming b = 1, we get: Z = (0.1641(2 - 1)/2)^0.5 + 1 = 26 Therefore, the metal that emits the KF1F1F1S1_F1F1F10 X-ray line is iron (Fe), with an atomic number of 26.

A K β\betaβ X-Ray Line of Wavelength 0

A K_$\beta$ X-Ray Line of Wavelength 0